document.write( "Question 867265: Solve
\n" ); document.write( "a)log(base 2)(x + 1)+ log(base 2)(x-1) = 3
\n" ); document.write( "b)log(base 2)(x^2-1) = 3
\n" ); document.write( "c)explain why the equations in part a and b are not equivalent
\n" ); document.write( "Can you please help me out? Thanks so much in advance:)
\n" ); document.write( "

Algebra.Com's Answer #522918 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
a)
\n" ); document.write( "log(base 2)(x + 1)+ log(base 2)(x-1) = 3
\n" ); document.write( "2^log(base 2)(x + 1)*2^log(base 2)(x-1)=2^3
\n" ); document.write( "(x+1)(x-1)=8
\n" ); document.write( "x^2=9
\n" ); document.write( "x=3
\n" ); document.write( ".
\n" ); document.write( "b)
\n" ); document.write( "log(base 2)(x^2-1) = 3
\n" ); document.write( "2^log(base 2)(x^2-1) =2^3
\n" ); document.write( "x^2-1=8
\n" ); document.write( "x^2=9
\n" ); document.write( "x=3, x=-3
\n" ); document.write( ".
\n" ); document.write( "c) x can't equal -1 in a) because a log cannot equal 0 or be negative.
\n" ); document.write( ".
\n" ); document.write( "Ed\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );