document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=867266>Question 867266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following exponential equations<BR>\n" );
document.write( "a) 3^(2x-1) = 2^(x+2)<BR>\n" );
document.write( "b) 2^(x+1) = 5^(1-x)<BR>\n" );
document.write( "c) 2^(x+1)/5^(x) = 3\r<BR>\n" );
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document.write( "Can you please help me out? Thanks so much in advance:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #522900 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=522900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the following exponential equations<BR>\n" );
document.write( "a) 3^(2x-1) = 2^(x+2)<BR>\n" );
document.write( "(2x-1)*log(3) = (x+2)*log(2)<BR>\n" );
document.write( "2x*log(3) - log(3) = x*log(2) + log(4)<BR>\n" );
document.write( "2x*log(3) - x*log(2) = log(3) + log(4) = log(12)<BR>\n" );
document.write( "x*log(9) - x*log(2) = log(3) + log(4) = log(12)<BR>\n" );
document.write( "x*(log(9) - log(2)) = log(12)<BR>\n" );
document.write( "x = log(12)/log(4.5)<BR>\n" );
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document.write( "The others are similar.\r<BR>\n" );
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document.write( "b) 2^(x+1) = 5^(1-x)<BR>\n" );
document.write( "c) 2^(x+1)/5^(x) = 3 </SPAN>\n" );
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