document.write( "Question 73027: When it says 'vertically stretch by a factor of.. , or vertically compress by a factor of.. , 'horizontally stretch by a factor of.. , or horizontally compress by a factor of.. ' is there some sort of calculation to use this factor and find additional points on the graph? I'm in section 3.1, starting with problem number 19. I understand the transformation processes of graphing these equations, I'm mainly looking for a way to know how to use that 'stretch/compress' factor to find additional points on the graph. Thank you for your help. \n" ); document.write( "
Algebra.Com's Answer #52281 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Let's say you start with the graph of a parabola: y=x^2
\n" ); document.write( "This is a statement regarding \"y\"; it is always \"the square of x\".
\n" ); document.write( "Now, look at y=3x^2
\n" ); document.write( "All those y-values are multiplied by 3; this \"stretches\" the curve so
\n" ); document.write( "it goes upward faster: the parabola will look narrower because it rises so fast.
\n" ); document.write( "Now look at y=(1/2)x^2
\n" ); document.write( "All those original y-values are multiplid by (1/2); this \"compresses\" the
\n" ); document.write( "curve so it looks flatter.
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\n" ); document.write( "There is no horizontal stretching or compressing but there is \"shifting\".
\n" ); document.write( "If you start with y=x^2 the vertex will occur at x=0
\n" ); document.write( "Replace \"x\" by \"x+3\" and the vertex will occur earlier on the x-axis; it will shift three to the left.
\n" ); document.write( "Replace \"x\" by \"x-3\" and the vertex will occur later on the x-axis; it will
\n" ); document.write( "shift three to the right.
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\n" ); document.write( "These are powerful tools for sketching curves. Learn how to use them and
\n" ); document.write( "you will save a lot of time you might otherwise use plotting points.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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