document.write( "Question 867170: Can any expert with math help me with this problem?\r
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document.write( "Count the probbaility of a bionominally distrubited random variable X to get the value of k = 0,1,2,3 for the occassions (n=10,p=0,1), (n=20,p=0,05), (n=100,p=0,01).
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document.write( "Count approximately the same probability, using the approach of Poisson for the bioniminal distribution. \n" );
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Algebra.Com's Answer #522797 by ewatrrr(24785)  You can put this solution on YOUR website! \n" );
document.write( "Hi \n" );
document.write( "NO problem: .01*100. it is. \n" );
document.write( "Re: TY. .01*100. = 1, \n" );
document.write( "Always a good idea though to check the Arithmetic on Probabilities \n" );
document.write( "Consider myself an Expert, only because I am a Doer. \n" );
document.write( "Have set Up a table and have DONE the Poisson Part of the Comparison: \n" );
document.write( "k avg Prob avg Prob avg Prob \n" );
document.write( "0 1 0.3679 1 0.3679 1 0.3679 \n" );
document.write( "1 1 0.3679 1 0.3679 1 0.3679 \n" );
document.write( "2 1 0.1839 1 0.1839 1 0.1839 \n" );
document.write( "3 1 0.0613 1 0.0613 1 0.0613 \n" );
document.write( "k Binom Prob Binom Prob Binom Prob \n" );
document.write( "0 n=10,p=.1 .3487 n=20,p=.05 .3585 n=100,p=.001 \n" );
document.write( "1 n=10,p=.1 .3874 n=20,p=.05 .3774 n=100,p=.001 \n" );
document.write( "2 n=10,p=.1 .1937 n=20,p=.05 .1887 n=100,p=.001 \n" );
document.write( "3 n=10,p=.1 .0574 n=20,p=.05 .0596 n=100,p=.001 \n" );
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