document.write( "Question 867108: George had a bottle filled with juice. He drank 1/5 of the juice in the bottle. An hour later, he drank 2 cups from what was left in the bottle. Two hours later, he drank 1/3 of the remaining juice in the bottle. Three hours later, George drank 2 1/2 cups of juice. Before going to bed, he drank 1/2 of what was left. George then measured the amount of juice left and found that there was still 3/4 of a cup of juice in the bottle. How much juice was originally in the bottle? \n" ); document.write( "
Algebra.Com's Answer #522715 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
p = number of cups volume originally in the bottle.\r
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\n" ); document.write( "\n" ); document.write( "act 1:
\n" ); document.write( "\"p-p%2F5\" cups in the bottle\r
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\n" ); document.write( "\n" ); document.write( "act 2:
\n" ); document.write( "\"p-p%2F5-2\" cups in the bottle\r
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\n" ); document.write( "\n" ); document.write( "act 3:
\n" ); document.write( "\"p-p%2F5-2-%281%2F3%29%28p-p%2F5-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "act 4:
\n" ); document.write( "\"p-p%2F5-2-%281%2F3%29%28p-p%2F5-2%29-5%2F2\", using \"5%2F2=2%261%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "act 5:
\n" ); document.write( "\"%281%2F2%29%28p-p%2F5-2-%281%2F3%29%28p-p%2F5-2%29-5%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Act 6:
\n" ); document.write( "Measurement made of how much juice still in the bottle.
\n" ); document.write( "\"highlight_green%28%281%2F2%29%28p-p%2F5-2-%281%2F3%29%28p-p%2F5-2%29-5%2F2%29=3%2F4%29\"
\n" ); document.write( "Solve for p.
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