document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=866963>Question 866963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Law of sines word problem help? \r<BR>\n" );
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document.write( "Points A and B are on opposite sides of a river. To find the distance between the points, a third point C is located on the same side of the river as point A. The distance between A and C is 50 feet, ACB is determined to be 47° and BAC is 115°. Find the distance between A and B.\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #522710 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=522710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Points A and B are on opposite sides of a river. To find the distance between the points, a third point C is located on the same side of the river as point A. The distance between A and C is 50 feet, ACB is determined to be 47° and BAC is 115°. Find the distance between A and B. <BR>\n" );
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document.write( "Given angle at point C=47&#730;<BR>\n" );
document.write( "Given angle at point A=115&#730;<BR>\n" );
document.write( "So the angle across the river at point B=180-115-47=18&#730;<BR>\n" );
document.write( "Using law of sines:<BR>\n" );
document.write( "sin 18/50=sin 47/AB<BR>\n" );
document.write( "AB=(sin 47/sin18)*50&#8776;118.34<BR>\n" );
document.write( "distance between A and B&#8776;118.34 ft </SPAN>\n" );
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