document.write( "Question 867052: The perimeter of a rectangle is 80 feet. Find the dimensions if the length is 5 feet longer than four times the width. Then find the area of the rectangle.
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Algebra.Com's Answer #522669 by josgarithmetic(39628) $\"\"$ $\"About$

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w and L;
\n" ); document.write( "L=3w+5;
\n" ); document.write( " $\"2w%2B2%283w%2B5%29=80\"$
\n" ); document.write( " $\"8w%2B10=80\"$
\n" ); document.write( " $\"4w%2B5=40\"$
\n" ); document.write( " $\"4w=35\"$
\n" ); document.write( " $\"highlight%28w=35%2F4%29\"$
\n" ); document.write( "-
\n" ); document.write( " $\"L=3%2835%2F4%29%2B5%284%2F4%29\"$
\n" ); document.write( " $\"L=%28105%2B20%29%2F4\"$
\n" ); document.write( " $\"highlight%28L=125%2F4%29\"$
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\n" ); document.write( "The dimension sizes kept in improper fraction form for ease in calculating the requested area.
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\n" ); document.write( "AREA, $\"wL=%2835%2F4%29%28125%2F4%29=highlight%284375%2F16%29\"$
\n" ); document.write( "Or
\n" ); document.write( " $\"highlight%28273%267%2F16%29\"$ square feet. \n" ); document.write( "

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