document.write( "Question 867020: an equation of the line that is perpendicular to 3X+6Y=12 and passes through the point (4,0) \n" ); document.write( "

Algebra.Com's Answer #522652 by mananth(16946) $\"\"$ $\"About$

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3 x + 6 y = 12
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "6 y = -3 x + 12
\n" ); document.write( "Divide by 6
\n" ); document.write( " y = - 1/ 2 x + 2
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = - 1/2
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 2
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be 2
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\n" ); document.write( "m= 2 ,point ( 4 , 0 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "0 = 8 + b
\n" ); document.write( "b= -8
\n" ); document.write( "m= 2
\n" ); document.write( "The required equation is y = 2 x-8
\n" ); document.write( "m.ananth@hotmail.ca
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