document.write( "Question 867004: I have a Linear Algebra question.
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document.write( "If Q is the vector space where f(x)=f^2(x) and f(x)=1 is Q a real vector space?
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document.write( "Assuming it is a subspace of F(Negative Infinity to Infinity) we only need to check the 2 axioms addition and scalar multiplication
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document.write( "1. Addition f(x) + f(x) = 1 + 1 = 2
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document.write( "Here is my question: f(x) = 2 isn't within the space, does that mean we don't have a Real vector space?
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Algebra.Com's Answer #522641 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! You are correct. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "According to this link, it says \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \"Closure: If u and v are any vectors in V, then the sum u + v belongs to V.\"\r \n" ); document.write( "\n" ); document.write( "Both f(x) = 1 and g(x) = 1 belong to the vector space Q, but h(x) = f(x) + g(x) = 2 does NOT belong to the vector space Q (since h^2(x) = 4, h(x) = 2, h^2(x) doesn't equal h(x))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So because the closure rule doesn't hold for all elements in Q, this means Q is NOT a vector space. \n" ); document.write( " |