document.write( "Question 866936: Solve the following equation for x:\r
\n" ); document.write( "\n" ); document.write( " e2x + ex -12 =0
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Algebra.Com's Answer #522595 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Substitute, $\"u=e%5Ex\"$ , then $\"u%5E2=e%5E%282x%29\"$
\n" ); document.write( " $\"u%5E2%2Bu-12=0\"$
\n" ); document.write( " $\"%28u%2B4%29%28u-3%29=0\"$
\n" ); document.write( "Two \"u\" solutions:
\n" ); document.write( " $\"u%2B4=0\"$
\n" ); document.write( " $\"u=-4\"$
\n" ); document.write( " $\"e%5E%28x%29=-4\"$
\n" ); document.write( "This is not a valid solution.
\n" ); document.write( " $\"u-3=0\"$
\n" ); document.write( " $\"u=3\"$
\n" ); document.write( " $\"e%5Ex=3\"$
\n" ); document.write( " $\"x=ln%283%29\"$
\n" ); document.write( " \n" ); document.write( "

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