document.write( "Question 866784: Rationalize the denominator..\r
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Algebra.Com's Answer #522540 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"A=sqrt%28a%2Bb%29\"$ and $\"B=sqrt%28a-b%29\"$
\n" ); document.write( " $\"%28A%2BB%29%2F%28A-B%29=%28%28A%2BB%29%2F%28A-B%29%29%2A%28%28A%2BB%29%2F%28A%2BB%29%29\"$
\n" ); document.write( " $\"%28A%2BB%29%2F%28A-B%29=%28A%5E2%2B2AB%2BB%5E2%29%2F%28A%5E2-B%5E2%29\"$
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\n" ); document.write( " $\"A%5E2=a%2Bb\"$
\n" ); document.write( " $\"B%5E2=a-b\"$
\n" ); document.write( " $\"A%5E2-B%5E2=2b\"$
\n" ); document.write( " $\"2AB=2sqrt%28%28a%2Bb%29%28a-b%29%29=2sqrt%28a%5E2-b%5E2%29\"$ }
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\n" ); document.write( "Putting it all together,
\n" ); document.write( " $\"%28A%2BB%29%2F%28A-B%29=%282%28a%2Bsqrt%28a%5E2-b%5E2%29%29%29%2F%282b%29\"$
\n" ); document.write( " $\"%28A%2BB%29%2F%28A-B%29=%28a%2Bsqrt%28a%5E2-b%5E2%29%29%2F%28b%29\"$
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