document.write( "Question 866821: The age of a man is twice the square of the age of his son.8 years hence, the age of the man will be 4 years more than 3 times the age of his son. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #522525 by dkppathak(439)![]() ![]() You can put this solution on YOUR website! The age of a man is twice the square of the age of his son.8 years hence, the age of the man will be 4 years more than 3 times the age of his son. Find their present ages. \n" ); document.write( "Let age of son is X yrs \n" ); document.write( "age of man will be 2X^2 \n" ); document.write( "8 yrs hence age of son will be= X+8 yrs \n" ); document.write( "8 yrs hence age of man will be =2X^2+8\r \n" ); document.write( "\n" ); document.write( "as per given conditions \n" ); document.write( "2X^2+8= 3(X+8)+4 \n" ); document.write( "X^2 +8 =3x+24+4 \n" ); document.write( "2x^2+8 =3x+28 \n" ); document.write( "2X^2-3x-20=0 \n" ); document.write( "2X^2-8X+5X-20=0 \n" ); document.write( "2x(x-4)+5(x-4)=0 \n" ); document.write( "(x-4)(2x+5)=0 \n" ); document.write( "x=4 or x=-5/2 \n" ); document.write( "neglecting negative value of age \n" ); document.write( "x=4 \n" ); document.write( "present age of son is 4 yrs \n" ); document.write( "present age of man is 32 yrs \n" ); document.write( " |