document.write( "Question 866755: A hollow container consists of a cylinder with a cone on top \r
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document.write( "The container contains oil up to the level of the top of the cylinder. the container is then turned upside down. Find the depth of the oil \r
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document.write( "Hight of cylinder = 6cm
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document.write( "width = 8cm \r
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document.write( "and hight of cone = 4cm \n" );
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Algebra.Com's Answer #522496 by Theo(13342)![]() ![]() You can put this solution on YOUR website! volume of the cylinder is equal to pi * r^2 * h \n" ); document.write( "h = 6 = height of cylinder. \n" ); document.write( "d = 8 = diameter of cylinder. \n" ); document.write( "r = 1/2 * 8 = 4 = radius of base of cylinder. \n" ); document.write( "v = pi * 4^2 * 6 = 96 * pi = 301.5928947.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "volume of the cone is equal to 1/3 * pi * r^2 * h \n" ); document.write( "h = 4 = height of the cone. \n" ); document.write( "r = 4 = radius of the base of the cone. \n" ); document.write( "v = 1/3 * pi * 4^2 * 4 = 64/3 * pi = 67.02064328.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when you invert the cylinder, the oil rushes into the cone and fills it up.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the volume of the cylinder is larger than the volume of the cone, there will be oil left over after the cone is full.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that left over oil goes into the cylinder.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the volume of oil that is left over is equal to 301.5928947 - 67.02064328 which is equal to 234.5722515.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is the volume of oil that is now in the cylinder.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation for the volume of the cylinder is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "v = pi * r^2 * h\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "pi stays the same at 3.141592654 and r stays the same at 4. \n" ); document.write( "v becomes 234.5722515 which is the volume of the oil that is now in the cylinder.\r \n" ); document.write( "\n" ); document.write( "since v = 234.5722515 and r = 4, the formula for the cylinder becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "234.5722515 = pi * 4^2 * h\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you want to solve for h.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get h = 234.5722515 / (16*pi).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for h to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "h = 4.6666..... which is equal to 4 2/3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that should be your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "confirm by adding up the volume in the cone and the volume in the cylinder.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "volume in the cone is equal to (1/3) * pi * 4^2 * 4 = 67.02064328 \n" ); document.write( "volume in the cylinder is equal to pi * 4^2 * 4.6666... = 234.5722515 \n" ); document.write( "total volume in cone and cylinder is equal to 301.5928947.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since this is the original volume of the oil in the cylinder before you turned the cylinder upside down, the value of h = 4 and 2/3 is good.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |