document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=866674>Question 866674</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the circle that passes through the given points.<BR>\n" );
document.write( "(7,6),(11,6),(9,4)\r<BR>\n" );
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document.write( "answer:____________________________ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #522466 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=522466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the circle goes through points<BR>\n" );
document.write( "(7,6),(11,6)<BR>\n" );
document.write( "the diameter =4 and radius =2<BR>\n" );
document.write( "and the center is at (9,6)<BR>\n" );
document.write( "(9,4) is also on the circle\r<BR>\n" );
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document.write( "(x-9)^2+(y-6)^2=4\r<BR>\n" );
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document.write( "These equations are valid and yield the same results as above<BR>\n" );
document.write( "(7-h)^2+(6-k)^2=r^2, <BR>\n" );
document.write( "(11-h)^2+(6-k)^2=r^2 ,<BR>\n" );
document.write( "(9-h)^2+(4-k)^2=r^2\r<BR>\n" );
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document.write( "h = 9,   k = 6,   r = 2<BR>\n" );
document.write( "(x-9)^2+(y-6)^2=4<BR>\n" );
document.write( " </SPAN>\n" );
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