document.write( "Question 866735: 20% of the population in Turkey is estimated to have green eyes. Out of a random group of 11 people in Turkey, what is the probability that exactly 4 have green eyes?
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document.write( "Round the percentage to the nearest whole number.\r
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document.write( "I got 40 when I did this. Is that correct? If not, how would I solve this type of equation? \n" );
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Algebra.Com's Answer #522450 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! You use the formula\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(n C k)*(p)^(k)*(1-p)^(n-k)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: n C k is found through the combination formula\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this case,\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 11 (sample size) \n" ); document.write( "p = 0.2 (probability of success, in this case, probability of picking someone with green eyes) \n" ); document.write( "k = 4 (number of exact successes you want)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So you'd have\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(n C k)*(p)^(k)*(1-p)^(n-k) \n" ); document.write( "(11 C 4)*(0.2)^(4)*(1-0.2)^(11-4) \n" ); document.write( "0.1107296256\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You would use a calculator to evaluate to get the last line shown above. That means we'd have a 0.1107296256*100 = 11.07296256% chance of picking exactly 4 people with green eyes.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the answer is actually 11% (and not 40%) \n" ); document.write( " |