document.write( "Question 866734: One roofing crew can finish a 2,800-square-foot roof in 12 hours, and another crew can do the job in 10 hours. If they work together, can they finish before a predict rain in 5 hours? \n" ); document.write( "
Algebra.Com's Answer #522447 by josgarithmetic(39617)\"\" \"About 
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The rates of each crew are:\r
\n" ); document.write( "\n" ); document.write( "\"1%2F12\" and \"1%2F10\" JOBS per HOUR.\r
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\n" ); document.write( "\n" ); document.write( "The way uniform rates situations go, \"R%2Ax=y\". In the kind of application for your example, x is time in hours and y is how much or many jobs. The unit of R is jobs per hour and R is a rate. The rate of each crew working together is the sum of their individual rates, so:\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F12%2B1%2F10=10%2F120%2B12%2F120=%2810%2B12%29%2F120=22%2F120=highlight%2811%2F60%29\" jobs per hour.\r
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\n" ); document.write( "\n" ); document.write( "Now, if rain will come in 5 hours, will this 5 hours be enough time to do ONE complete job?\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28%2811%2F60%29%2A5%3E=1%29\" ? Is this true or false?\r
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\n" ); document.write( "\n" ); document.write( "\"55%2F60%3E=1\" FALSE.
\n" ); document.write( "The two crews together will not be able to finish the roof before the rain prediction time.
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