document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846226>Question 846226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a rectangle is 48 square yards. its length is 10 yards less than twice the width. find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #522431 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=522431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) 48=lw\r<BR>\n" );
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document.write( "2) l=2w-10\r<BR>\n" );
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document.write( "48=(2w-10)w<BR>\n" );
document.write( "24=w^2-5w<BR>\n" );
document.write( "w^2-5w-24=0<BR>\n" );
document.write( "(w-8)(w+3)=0\r<BR>\n" );
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document.write( "w=8 so l=6 </SPAN>\n" );
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