document.write( "Question 866674: Write the equation of the circle that passes through the given points.
\n" ); document.write( "(7,6),(11,6),(9,4)\r
\n" ); document.write( "\n" ); document.write( "answer:____________________________
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Algebra.Com's Answer #522424 by josgarithmetic(39799)\"\" \"About 
You can put this solution on YOUR website!
Using the standard form equation for a circle, you can make three separate equations for a system:\r
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\n" ); document.write( "\"%287-h%29%5E2%2B%286-k%29%5E2=r%5E2\"
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\n" ); document.write( "\"%2811-h%29%5E2%2B%286-k%29%5E2=r%5E2\"
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\n" ); document.write( "\"%289-h%29%5E2%2B%284-k%29%5E2=r%5E2\"
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\n" ); document.write( "\n" ); document.write( "Equating the left members of the first two equations, based on both equal to \"r%5E2\" and that both members contain \"%286-k%29%5E2\", allows you to find a value for h.\r
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\n" ); document.write( "\n" ); document.write( "You can use this value for h to turn the variable expression in each of the three equations into a constant term; so now you will have three equations and just TWO unknowns, k and r.\r
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\n" ); document.write( "\n" ); document.write( "I started this separately myself on paper, but not yet finished...
\n" ); document.write( "This part just for h, but omitting to show the steps of the process: \"highlight_green%28h=-2%29\"...\r
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\n" ); document.write( "\n" ); document.write( "Using that \"h=-2\", the equation Number 2 and Number 3 become:
\n" ); document.write( "\"169%2B%286-k%29%5E2=r%5E2\"
\n" ); document.write( "and
\n" ); document.write( "\"121%2B%284-k%29%5E2=r%5E2\"
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\n" ); document.write( "Now equation each expression for both being \"r%5E2\", this gives \"169%2B%286-k%29%5E2=121%2B%284-k%29%5E2\".
\n" ); document.write( "Performing the arithmetic, algebraic steps gives...
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\n" ); document.write( "\"highlight_green%28k=17%29\".\r
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\n" ); document.write( "\n" ); document.write( "Use any of the original or transformed equations of the system to compute the value of r.
\n" ); document.write( "\"81%2B%286-%28-17%29%29%5E2=r%5E2\"
\n" ); document.write( "\"81%2B23%5E2=r%5E2\"
\n" ); document.write( "\"r%5E2=81%2B529\"
\n" ); document.write( "\"highlight_green%28r%5E2=610%29\"-----see that this is still in the squared form.
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\n" ); document.write( "The equation of the circle should be: \"highlight%28%28x%2B2%29%5E2%2B%28y-17%29%5E2=610%29\".
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