document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=866650>Question 866650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A die is tossed 12 times. What is the probability of getting exactly three 3's? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #522413 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=522413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a binomial distribution problem with p = 1/6 (that's the probability of rolling a single 3), n = 12\r<BR>\n" );
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document.write( "In this case, x = 3 since we want exactly 3 threes.\r<BR>\n" );
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document.write( "Now compute n C x = 12 C 3 = (12!)/(3!*(12-3)!) = 220. This is the binomial coefficient.\r<BR>\n" );
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document.write( "So we'll then have 220*p^(x)*(1-p)^(n-x) = 220*(1/6)^(3)*(1-1/6)^(12-3) = 0.19739571242092\r<BR>\n" );
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document.write( "So the probability of getting exactly 3 threes is approximately <font color=\"red\">0.19739571242092</font> (roughly 19.73957%) </SPAN>\n" );
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