document.write( "Question 866480: Archeologists can use the known decay rate of Carbon- 14 to estimate the age of organic objects. Suppose Illinois Jones has discovered a wooden spear in a cave. If the wood contains 12% of it s original amount of Carbon- 14, approximately how old is the spear? The half-life of Carbon-14 is 5730. \n" ); document.write( "
Algebra.Com's Answer #522410 by ankor@dixie-net.com(22740)\"\" \"About 
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Archeologists can use the known decay rate of Carbon- 14 to estimate the age of organic objects.
\n" ); document.write( " If the wood contains 12% of it s original amount of Carbon- 14, approximately how old is the spear?
\n" ); document.write( " The half-life of Carbon-14 is 5730.
\n" ); document.write( ":
\n" ); document.write( "Use the radioactive decay formula: A = Ao*2^(-t/h); where:
\n" ); document.write( "A = remaining amt after t time
\n" ); document.write( "Ao = initial amt
\n" ); document.write( "t = time of decay
\n" ); document.write( "h = half-life of substance
\n" ); document.write( ":
\n" ); document.write( "let initial amt = 1, then remaining amt = .12
\n" ); document.write( "1*2^(-t/5730) = .12
\n" ); document.write( "using logs
\n" ); document.write( "\"-t%2F5730\" = \"log%28.12%29%2Flog%282%29\"
\n" ); document.write( "\"-t%2F5730\" = -3.05889
\n" ); document.write( "t = -3.05889 * 5730
\n" ); document.write( "t = 17,527 yrs is the age of the wood
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