document.write( "Question 866635: The perimeter of a rectangular field is 168 feet, the field is 36 feet wide. How long is the field?
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Algebra.Com's Answer #522389 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! P = 168 (given perimeter) \n" ); document.write( "W = 36 (given width) \n" ); document.write( "L = unknown (we'll leave it as L for now)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 2*(L+W) ... perimeter of rectangle formula\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "168 = 2*(L+36) ... plug in L = 36 and P = 168, then solve for L (ie isolate it)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "168 = 2*L+2*36\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "168 = 2L+72\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "168-72 = 2L\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "96 = 2L\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2L = 96\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 96/2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 48\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The length of the field is 48 feet \n" ); document.write( " |