document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=866607>Question 866607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 75 m long. The length of one leg is 51 m less than the other. Find the length of the legs </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #522385 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=522385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since it is right triangle\r<BR>\n" );
document.write( "\n" );
document.write( "x^2+(x-51)^2=75^2 ( Pythagoras theorem)\r<BR>\n" );
document.write( "\n" );
document.write( "x^2+x^2-102x +2601= 5625\r<BR>\n" );
document.write( "\n" );
document.write( "2x^2-102x-3024=0\r<BR>\n" );
document.write( "\n" );
document.write( "/2<BR>\n" );
document.write( "x^2-51x-1512=0\r<BR>\n" );
document.write( "\n" );
document.write( "x^2-72x+21x-1512=0\r<BR>\n" );
document.write( "\n" );
document.write( "x(x-72)+21(x-72)=0\r<BR>\n" );
document.write( "\n" );
document.write( "(x-72)(x+21)=0\r<BR>\n" );
document.write( "\n" );
document.write( "x=72 OR -21\r<BR>\n" );
document.write( "\n" );
document.write( "ignore negative<BR>\n" );
document.write( "x= 72 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );