document.write( "Question 866322: A nutrition lab tests 60 reduced fat hit dogs. This sample produces a mean of 318 mg of sodium, and the standard deviation is 32 mg.\r
\n" ); document.write( "\n" ); document.write( "a) What is the standard error for the mean sodium content?\r
\n" ); document.write( "\n" ); document.write( "b) Find and interpret a 95 confidence interval.\r
\n" ); document.write( "\n" ); document.write( "c) Food labeling regulations require that any food identified as \"reduced sodium\" must have at least 30% less sodium than it's regular counterpart. If regular franks average 465 mg of sodium, should this brand be labeled \"reduced\"? Explain using your confidence interval.
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Algebra.Com's Answer #522295 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "mean of 318 mg of sodium, and the standard deviation is 32 mg.
\n" ); document.write( "n = 60
\n" ); document.write( "a) SE = 32/sqrt(60)= 4.1312
\n" ); document.write( "b) ME = 1.96(4.1312) = 8
\n" ); document.write( "CI: 318-8 < u < 318 + 8 (310, 336)
\n" ); document.write( "c) .7(465) = 325.5, Yes reduced. It is in the confidence Interval\r
\n" ); document.write( "\n" ); document.write( "CI z -value
\n" ); document.write( "90% z =1.645
\n" ); document.write( "92% z = 1.751
\n" ); document.write( "95% z = 1.96
\n" ); document.write( "98% z = 2.326
\n" ); document.write( "99% z = 2.576
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