document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72980>Question 72980</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1565771400/algebrahomeworkh>Algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> i actually have a few questions some aren't really about the topic...a few being 5...\r<BR>\n" );
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document.write( "1. Two kilograms of iron was melted with 7 kilograms of other metals to make the alloy. If 1440 kilograms of the alloy was required, how many kilograms of iron should be used?\r<BR>\n" );
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document.write( "2. Charles and Matthew knew that the formula for sulfuric acid was H2SO. If they haad 196 grams of sulfuric acid, what was the weight of the sulfur(H,1; S,32; O,16)?\r<BR>\n" );
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document.write( "3. The ratio of the two numbers was 7 to 2. When Sir Richard and MArion multiplied the denominator by 10, they found that the result was 84 greater than twice the numerator. What were the numbers?\r<BR>\n" );
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document.write( "4. Solve: 5x-2 over(/) 3 -x over(/) 4 = 7\r<BR>\n" );
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document.write( "5. 1 over (/) x+3 + 3x over(/) x+2 + 2x+1 over(/) x squared + 5x + 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52226 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Two kilograms of iron was melted with 7 kilograms of other metals to make the alloy. If 1440 kilograms of the alloy was required, how many kilograms of iron should be used?<BR>\n" );
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document.write( "the total is 2 + 7 = 9: Relationship of iron to the total: 2:9<BR>\n" );
document.write( "Let I = kilos of iron<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F9 ALIGN=MIDDLE  ALT=\"2%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" > =<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=I%2F1440 ALIGN=MIDDLE  ALT=\"I%2F1440\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Cross multiply:<BR>\n" );
document.write( "9I = 2(1440)<BR>\n" );
document.write( "9I = 2880<BR>\n" );
document.write( "I = 2880/9<BR>\n" );
document.write( "I = 320 kilos of iron in 1440 kilos of alloy<BR>\n" );
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document.write( "2. Charles and Matthew knew that the formula for sulfuric acid was H2SO. If they had 196 grams of sulfuric acid, what was the weight of the sulfur(H,1; S,32; O,16)?<BR>\n" );
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document.write( "The relationship of a sulfur weight to the total: 32:(2+32+16) = 32:50<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=32%2F50 ALIGN=MIDDLE  ALT=\"32%2F50\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%2F196 ALIGN=MIDDLE  ALT=\"S%2F196\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Cross multiply:<BR>\n" );
document.write( "50S = 6272<BR>\n" );
document.write( "s = 6272/50<BR>\n" );
document.write( "s = 125.44 grams of sulfur in 196 grams of H2SO<BR>\n" );
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document.write( "3. The ratio of the two numbers was 7 to 2. When Sir Richard and MArion multiplied the denominator by 10, they found that the result was 84 greater than twice the numerator. What were the numbers?<BR>\n" );
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document.write( "\"The ratio of the two numbers was 7 to 2\"<BR>\n" );
document.write( "Let x = the multiplier<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%287x%29%2F%282x%29 ALIGN=MIDDLE  ALT=\"%287x%29%2F%282x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "\"Multiply the denominator (2x) by 10. <BR>\n" );
document.write( "Result is 84 greater than twice the numerator (7x)\"<BR>\n" );
document.write( "10(2x) = 2(7x) + 84<BR>\n" );
document.write( "20x = 14x + 84<BR>\n" );
document.write( "20x - 14x = 84<BR>\n" );
document.write( "6x = 84<BR>\n" );
document.write( "x = 14 is the multiplier<BR>\n" );
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document.write( "Therefore the numbers are: (14*7) and 14(2) or 98 and 28  <BR>\n" );
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document.write( "4. Solve: 5x-2 over(/) 3 -x over(/) 4 = 7<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%285x-2%29%29%2F3 ALIGN=MIDDLE  ALT=\"%28%285x-2%29%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F4 ALIGN=MIDDLE  ALT=\"x%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 7<BR>\n" );
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document.write( "Multiplying equation by 12 gets rid of the denominators:<BR>\n" );
document.write( "4(5x-2) - 3(x) = 12(7)<BR>\n" );
document.write( "20x - 8 - 3x = 84<BR>\n" );
document.write( "20x - 3x = 84 + 8<BR>\n" );
document.write( "17x = 92<BR>\n" );
document.write( "x = 92/17<BR>\n" );
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document.write( "5. 1 over (/) x+3 + 3x over(/) x+2 + 2x+1 over(/) x squared + 5x + 6<BR>\n" );
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document.write( "The way I understand it:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F%28x%2B3%29+%2B+3x%2F%28x%2B2%29+%2B+%282x%2B1%29%2F%28x%5E2+%2B+5x+%2B+6%29 ALIGN=MIDDLE  ALT=\"1%2F%28x%2B3%29+%2B+3x%2F%28x%2B2%29+%2B+%282x%2B1%29%2F%28x%5E2+%2B+5x+%2B+6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The last denominator can be factored to the same values as the other 2 denominators:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F%28x%2B3%29+%2B+3x%2F%28x%2B2%29+%2B+%282x%2B1%29%2F%28%28x%2B2%29%28x%2B3%29%29 ALIGN=MIDDLE  ALT=\"1%2F%28x%2B3%29+%2B+3x%2F%28x%2B2%29+%2B+%282x%2B1%29%2F%28%28x%2B2%29%28x%2B3%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "(x+3)(x+2) is the common denominator<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%28x%2B2%29+%2B+3x%28x%2B3%29+%2B+%282x%2B1%29%29%2F%28%28x%2B2%29%28x%2B3%29%29 ALIGN=MIDDLE  ALT=\"%281%28x%2B2%29+%2B+3x%28x%2B3%29+%2B+%282x%2B1%29%29%2F%28%28x%2B2%29%28x%2B3%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x+%2B+2+%2B+3x%5E2+%2B+9x+%2B+2x+%2B+1+%29%2F%28%28x%2B3%29%28x%2B2%29%29 ALIGN=MIDDLE  ALT=\"%28x+%2B+2+%2B+3x%5E2+%2B+9x+%2B+2x+%2B+1+%29%2F%28%28x%2B3%29%28x%2B2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28+3x%5E2+%2B+12x+%2B+3+%29%2F%28%28x%2B3%29%28x%2B2%29%29 ALIGN=MIDDLE  ALT=\"%28+3x%5E2+%2B+12x+%2B+3+%29%2F%28%28x%2B3%29%28x%2B2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28+3%28x%5E2+%2B+4x+%2B+1+%29%29%2F%28%28x%2B3%29%28x%2B2%29%29 ALIGN=MIDDLE  ALT=\"%28+3%28x%5E2+%2B+4x+%2B+1+%29%29%2F%28%28x%2B3%29%28x%2B2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "That's about as far as you can go with it\r<BR>\n" );
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document.write( " </SPAN>\n" );
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