document.write( "Question 866321: FIND THE SUM OF TWO DIGIT NUMBERS WHICH BEING DIVIDED BY 4 LEAVE A REMAINDER OF 1.
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Algebra.Com's Answer #522257 by MathLover1(20850) $\"\"$ $\"About$

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the number is of the form $\"4x%2B1\"$ by definition where $\"x\"$ is a natural number \r
\n" ); document.write( "\n" ); document.write( " first such 2 digit number is $\"4%2A3%2B1=13+\"$
\n" ); document.write( " last such 2 digit number is $\"4%2A24%2B1=97+\"$ \r
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\n" ); document.write( "\n" ); document.write( "this is an arithmetic progression with common difference $\"4\"$ \r
\n" ); document.write( "\n" ); document.write( "so, we have $\"13\"$ , $\"17\"$ , $\"21\"$ , $\"25\"$ , $\"29\"$ , $\"33\"$ , $\"37%7D%7D%5D%2C%7B%7B%7B41\"$ , $\"45\"$ , $\"49\"$ , $\"53\"$ , $\"57\"$ , $\"61\"$ , $\"65\"$ , $\"69\"$ , $\"73\"$ , $\"77\"$ , $\"81\"$ , $\"85\"$ , $\"89\"$ , $\"93\"$ , $\"97\"$ \r
\n" ); document.write( "\n" ); document.write( "the sum is given by $\"sum=%28n%2F2%29%282a%2B%28n-1%29%2Ad%29+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"n\"$ is the number of terms, $\"a\"$ is the first number, $\"d\"$ is the common difference \r
\n" ); document.write( "\n" ); document.write( " $\"n=%2897-13%29%2F4%2B1=22+\"$
\n" ); document.write( " $\"a=13\"$
\n" ); document.write( " $\"d=4\"$
\n" ); document.write( " $\"sum=%2822%2F2%29%2A%282%2A13%2B21%2A4%29=+11%28110%29=1210+\"$ \r
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