document.write( "Question 866318: How many points in the interval 0 ≤ x ≤ 2π satisfy the equation cos 2x = –2 sin x?
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Algebra.Com's Answer #522228 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How many points in the interval 0 ≤ x ≤ 2π satisfy the equation cos 2x = –2 sin x?
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\n" ); document.write( "cos(2x) = -2sin(x)
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\n" ); document.write( "1-2sin^2(x) = -2sin(x)
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\n" ); document.write( "2sin^2(x) -2sin(x) - 1 = 0
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\n" ); document.write( "sin((x) = [2 +- sqrt(4-4*2*-1)]/4
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\n" ); document.write( "sin(x) = [2+-sqrt(12)]/4
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\n" ); document.write( "sin(x = [2[1+-sqrt(3)]/4
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\n" ); document.write( "sin(x) = (1/2)(1+sqrt(3)) or sin(x) = (1/2)(1-sqrt(3))
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\n" ); document.write( "Note:: (1/2)(1+sqrt(3) > 1 so no solutions there
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\n" ); document.write( "(1/2)(1-sqrt(3)) = -0.3660, so there are 2 solutions,
\n" ); document.write( "one in QIII, the other in QIV.
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\n" ); document.write( "Cheers,
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