document.write( "Question 866306: the ratio of the volume to the area of the right circularcone is 3:1, if the altitude is 12cm. what is the volume of the right circular cone? \n" ); document.write( "
Algebra.Com's Answer #522225 by dkppathak(439)\"\" \"About 
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the ratio of the volume to the area of the right circularcone is 3:1, if the altitude is 12cm. what is the volume of the right circular cone?
\n" ); document.write( "Answer volume of cone =1/3 pie r^2 h
\n" ); document.write( "area of cone =pie r l
\n" ); document.write( "ratio of volume : area =3:1
\n" ); document.write( "1/3 pie r^2 h :pie r l =3:1
\n" ); document.write( "r h/3l = 3/1 (by cross multiplication)
\n" ); document.write( "9l = rh squaring both side
\n" ); document.write( "81l^2=r^2 h^2 ( we know l^2=r^2+h^2)
\n" ); document.write( " 81(r^2+h^2)=r^2 h^2 given than h=12
\n" ); document.write( "81(r^2+12^2)= r^2 x 12^2
\n" ); document.write( "81 r^2 + 81 x 144= 144 r^2
\n" ); document.write( "11664 = 144 r^2-81 r^2
\n" ); document.write( "1296= 63 r^2
\n" ); document.write( "r^2=11664/63
\n" ); document.write( "r^2=185.14
\n" ); document.write( "volume =1/3 x 22/7 x r^2 x 12 by putting the value of r^2 = 185.14
\n" ); document.write( "volume =1/3 x 22/7 x 185.14 x 12= 1 x 22 x 185.14 x 12/3 x 7 =
\n" ); document.write( " 48876.96/21=2327.47 cubic cm\r
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