document.write( "Question 866293: Solve this system of equations:\r
\n" ); document.write( "\n" ); document.write( "y=x^2-2x-1
\n" ); document.write( "y=-x^2+4x-1\r
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Algebra.Com's Answer #522170 by farbonara(13)\"\" \"About 
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y=x^2-2x-1 ---(1)
\n" ); document.write( "y=-x^2+4x-1 ---(2)\r
\n" ); document.write( "\n" ); document.write( "(1)=(2)
\n" ); document.write( "x^2-2x-1=-x^2+4x-1
\n" ); document.write( "2x^2-6x=0
\n" ); document.write( "x^2-3x=0
\n" ); document.write( "(x)(x-3)=0
\n" ); document.write( "x=0 or x=3\r
\n" ); document.write( "\n" ); document.write( "Using (1),
\n" ); document.write( "When x=0,y=-1
\n" ); document.write( "When x=3,y=2
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