document.write( "Question 866238: Find the exact value of the given expression.\r
\n" ); document.write( "\n" ); document.write( "tan(1/2 cos^-1(2/3))
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Algebra.Com's Answer #522159 by lwsshak3(11628)\"\" \"About 
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Find the exact value of the given expression.
\n" ); document.write( "tan(1/2 cos^-1(2/3))
\n" ); document.write( "let x=angle whose cos=2/3
\n" ); document.write( "cosx=2/3
\n" ); document.write( "sinx=√(1-cos^2x)=√(1-4/9)=√(5/9)=√5/3
\n" ); document.write( "tan(1/2 cos^-1(2/3))=tan(x/2)
\n" ); document.write( "Identity: tan(x/2)=sinx/(1+cosx)=(√5/3)/(1+(2/3))=(√5/3)/(5/3)=√5/5
\n" ); document.write( "calculator check:
\n" ); document.write( "cosx=2/3
\n" ); document.write( "x≈48.19˚
\n" ); document.write( "x/2≈24.09
\n" ); document.write( "tan(x/2)≈tan(24.09)≈0.4471…
\n" ); document.write( "exact value as calculated=√5/5≈0.4471…
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