document.write( "Question 866234: A financial advisor invested a total of $10000 , part at 7.5% per annum compounded annually, part at 8% per annum compounded annually. At the end of the first year, a total of $780 interest had been earned. How much had been invested at each interest rate? \n" ); document.write( "
Algebra.Com's Answer #522148 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 7.50% per annum ------------- Amount invested =x \n" ); document.write( "Part II 8.00% per annum ------------ Amount invested = y \n" ); document.write( " 10000 \n" ); document.write( "Interest----- 780.00 \n" ); document.write( " \n" ); document.write( "Part I 7.50% per annum ---x \n" ); document.write( "Part II 8.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 10000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "7.50% x + 8.00% y= 780 \n" ); document.write( "Multiply by 100 \n" ); document.write( "7.5 x + 8 y= 78000.00 --------2 \n" ); document.write( "Multiply (1) by -7.5 \n" ); document.write( "we get \n" ); document.write( "-7.5 x -7.5 y= -75000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 0.5 y= 3000 \n" ); document.write( "divide by 0.5 \n" ); document.write( " y = 6000 \n" ); document.write( "Part I 7.50% $ 4000 \n" ); document.write( "Part II 8.00% $ 6000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "4000 --------- 7.50% ------- 300.00 \n" ); document.write( "6000 ------------- 8.00% ------- 480.00 \n" ); document.write( "Total -------------------- 780.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |