document.write( "Question 866209: Given the line 2x – 3y = 9 and the point (4, –1), find lines through the point that are \r
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\n" ); document.write( "\n" ); document.write( "(a) parallel to the given line and
\n" ); document.write( " (b) perpendicular to it.
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Algebra.Com's Answer #522124 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Given the line 2x – 3y = 9 and the point (4, –1), find lines through the point that are
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\n" ); document.write( "Find the slope of the give line:
\n" ); document.write( "3y = 2x-9
\n" ); document.write( "y = (2/3)x - 3
\n" ); document.write( "slope = 2/3
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\n" ); document.write( "\n" ); document.write( "(a) parallel to the given line
\n" ); document.write( "slope must be (2/3)
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\n" ); document.write( "Form:: y = mx + b
\n" ); document.write( "Solve for \"b\" using the point and slope.
\n" ); document.write( "-1 = (2/3)4 + b
\n" ); document.write( "-3/3 = 8/3 + b
\n" ); document.write( "b = -11/3
\n" ); document.write( "Equation:
\n" ); document.write( "y = (2/3)x - (11/3)
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\n" ); document.write( "\n" ); document.write( "(b) perpendicular to it
\n" ); document.write( "slope must be -3/2
\n" ); document.write( "Form: y = mx + b
\n" ); document.write( "Solve for \"b\" using the point and slope
\n" ); document.write( "-1 = (-3/2)4 + b
\n" ); document.write( "-1 = -6 = b
\n" ); document.write( "b = 5
\n" ); document.write( "Equation:
\n" ); document.write( "y = (-3/2)x + 5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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