document.write( "Question 866209: Given the line 2x – 3y = 9 and the point (4, –1), find lines through the point that are \r
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document.write( "(a) parallel to the given line and
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document.write( " (b) perpendicular to it.
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Algebra.Com's Answer #522124 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Given the line 2x – 3y = 9 and the point (4, –1), find lines through the point that are \n" ); document.write( "------------------- \n" ); document.write( "Find the slope of the give line: \n" ); document.write( "3y = 2x-9 \n" ); document.write( "y = (2/3)x - 3 \n" ); document.write( "slope = 2/3 \n" ); document.write( "-------------------------------- \r \n" ); document.write( "\n" ); document.write( "(a) parallel to the given line \n" ); document.write( "slope must be (2/3) \n" ); document.write( "-- \n" ); document.write( "Form:: y = mx + b \n" ); document.write( "Solve for \"b\" using the point and slope. \n" ); document.write( "-1 = (2/3)4 + b \n" ); document.write( "-3/3 = 8/3 + b \n" ); document.write( "b = -11/3 \n" ); document.write( "Equation: \n" ); document.write( "y = (2/3)x - (11/3) \n" ); document.write( "=============================\r \n" ); document.write( "\n" ); document.write( "(b) perpendicular to it \n" ); document.write( "slope must be -3/2 \n" ); document.write( "Form: y = mx + b \n" ); document.write( "Solve for \"b\" using the point and slope \n" ); document.write( "-1 = (-3/2)4 + b \n" ); document.write( "-1 = -6 = b \n" ); document.write( "b = 5 \n" ); document.write( "Equation: \n" ); document.write( "y = (-3/2)x + 5 \n" ); document.write( "----------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |