document.write( "Question 866137: The area of the front cover of a daily journal is 273 cm^2 and the length is 8 cm greater than the width. What are the dimensions of the cover? \n" ); document.write( "
Algebra.Com's Answer #522114 by farbonara(13)![]() ![]() ![]() You can put this solution on YOUR website! Let length be L and width be W\r \n" ); document.write( "\n" ); document.write( "L x W = 273 ---(1) \n" ); document.write( "L - W = 8 ---(2)\r \n" ); document.write( "\n" ); document.write( "Rearranging (2), \n" ); document.write( "L = 8 + W ---(3)\r \n" ); document.write( "\n" ); document.write( "Substitute (3) into (1) \n" ); document.write( "(8+W) x W = 273 \n" ); document.write( "8W + W^2 = 273 \n" ); document.write( "W^2 + 8W - 273 = 0 \n" ); document.write( "(W+21)(W-13) = 0 \n" ); document.write( "W=-21(reject) or W=13\r \n" ); document.write( "\n" ); document.write( "Using (3), \n" ); document.write( "L=8+13=21 \n" ); document.write( " |