document.write( "Question 866131: In an unknown fraction the denominator is one more than twice the numerator.When 2 (1/10) is added to this fraction,the result is equal to the reciprocal of the unknown fraction.find the unkown fraction. \n" ); document.write( "
Algebra.Com's Answer #522107 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
In an unknown fraction the denominator is one more than twice the numerator.
\n" ); document.write( "When 2 (1/10) is added to this fraction,the result is equal to the reciprocal of the unknown fraction.
\n" ); document.write( "find the unknown fraction.
\n" ); document.write( ":
\n" ); document.write( "Let x = the numerator of the unknown fraction
\n" ); document.write( "then \"the denominator is one more than twice the numerator\", therefore:
\n" ); document.write( "(2x+1) = the denominator
\n" ); document.write( ":
\n" ); document.write( "Change 2\"1%2F10\" to \"21%2F10\"
\n" ); document.write( ":
\n" ); document.write( "\"When 2 (1/10) is added to this fraction,the result is equal to the reciprocal of the unknown fraction.\"
\n" ); document.write( "\"x%2F%28%282x%2B1%29%29\" + \"21%2F10\" = \"%28%282x%2B1%29%29%2Fx\"
\n" ); document.write( "mult equation by 10x(2x+1), cancel the denominators and you have
\n" ); document.write( "10x(x) + 21x(2x+1) = 10(2x+1)(2x+1)
\n" ); document.write( "10x^2 + 42x^2 + 21x = 10(4x^2 + 4x + 1)
\n" ); document.write( "52x^2 + 21x = 40x^2 + 40x + 10
\n" ); document.write( "combine like terms on the left
\n" ); document.write( "52x^2 - 40x^2 + 21x - 40x - 10 = 0
\n" ); document.write( "12x^2 - 19x - 10 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(12x + 5)(x - 2) = 0
\n" ); document.write( "only the positive integer makes sense here
\n" ); document.write( "x = 2
\n" ); document.write( "then the unknown fraction:
\n" ); document.write( "\"2%2F%28%282%282%29%2B1%29%29\" = \"2%2F5\"
\n" ); document.write( ":
\n" ); document.write( ":\
\n" ); document.write( "Check this
\n" ); document.write( "\"2%2F5\" + \"21%2F10\" = \"5%2F2\"
\n" ); document.write( "
\n" ); document.write( "
\n" );