document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=866098>Question 866098</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	a) 	The first four terms of a sequence are given as<BR>\n" );
document.write( "			2/3  ,-2/9  ,    2/27  ,-2/81<BR>\n" );
document.write( "(i)	Determine U_n, the general form for the n^th term of the sequence 		[2]<BR>\n" );
document.write( "(ii)	Calculate the difference between the 10th and 8th term of the sequence.	[3]\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #522074 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=522074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r=-1/3<BR>\n" );
document.write( "i) Tn = 2/3 *(-1/3)^(n - 1)<BR>\n" );
document.write( "Tn = 2/3 *(-1/3)^(9)=-2/59049 <BR>\n" );
document.write( "Tn = 2/3 *(-1/3)^(7)=-2/6561 <BR>\n" );
document.write( "ii) D=2/3 *(-1/3)^(9)-2/3*(-1/3)^(7)=16/59049 \r<BR>\n" );
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