document.write( "Question 866028: In a survey of 2480 golfers, 15% said they were left-handed. The survey margin of error was 3%. Construct a confidences interval for the proportion do the left handed golfers? \r
\n" ); document.write( "\n" ); document.write( "Please help I don't even know how to start to solve it! \n" ); document.write( "

Algebra.Com's Answer #522036 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "Hi
\n" );
document.write( "15% said they were left-handed. ME =  3%.
\n" );
document.write( " CI: p-ME < p <  p + ME
\n" );
document.write( "Ci: 12% < p < 18%
\n" );
document.write( " \n" );
document.write( "

\n" );