document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72962>Question 72962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jill is 8 kilometers away from Joe. Both began to walk toward each other at the same time, Jill walks at 1. kilometers and hour they meet in two hours, how fast is Joe walking </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52198 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) = rate(r) times time(t) or d=rt and r=d/t\r<BR>\n" );
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document.write( "Let r= Joe's rate (how fast he's walking) \r<BR>\n" );
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document.write( "In 2 hours Jill walks 2 kilometers (d=1*2) that leaves 6 kilometers (8-2) for Joe to walk in 2 hours\r<BR>\n" );
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document.write( "r=6/2=3 kilometers/hour-----------------------------------Joe's speed\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "1 kilometer/hour times 2 hours plus 3 kilometers/hour times 2 hours =8 kilometers<BR>\n" );
document.write( "8 kilometers=8 kilometers<BR>\n" );
document.write( "Both together walked 8 kilometers\r<BR>\n" );
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document.write( "Hope this helps-----ptaylor </SPAN>\n" );
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