document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=845846>Question 845846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the compound inequality |3x-9| < 15 AND |2x-3| > 5 (which reads \"The absolute value of 3x-9 is less than or equal to 15. AND The absolute value of 2x-3 is greater than or equal to 5\" Give answer in interval notation.<BR>\n" );
document.write( "When I solve for each I get as far as the first being -2<_|x|<_24 and that the 2nd is -4>_|x|>_2. X cannot be both greater than -2 and less than -4 so I think it would be an empty set? Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521900 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)<BR>\n" );
document.write( "-15 < 3x-9 < 15<BR>\n" );
document.write( "-15+9 < 3x < 15+9<BR>\n" );
document.write( "-6 < 3x < 24<BR>\n" );
document.write( "-2 < x < 8\r<BR>\n" );
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document.write( "(-2,8)\r<BR>\n" );
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document.write( "2)<BR>\n" );
document.write( "2x-3 < -5   or   2x-3 > 5<BR>\n" );
document.write( "2x < -2   or  2x > 8<BR>\n" );
document.write( "x < -1  or  x > 4\r<BR>\n" );
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document.write( "(-oo,-1)U(4,oo)\r<BR>\n" );
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document.write( "intersection:\r<BR>\n" );
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document.write( "(-2,-1) U (4,8) </SPAN>\n" );
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