document.write( "Question 865839: \"+log%28+2%2C+1+%29+\" - \"+log%28+4%2C+x+%29+\" + \"+log%28+4%2C+y+%29+\" = 2\r
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Algebra.Com's Answer #521878 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Change the base-four logs into base-two logs, using Change Of Base formula.\r
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\n" ); document.write( "As a side step, \"log%282%2C4%29=log%282%2C2%5E2%29=2%2Alog%282%2C2%29=2%2A1=2\"
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\n" ); document.write( "\"0-log%282%2Cx%29%2F2%2Blog%282%2Cy%29%2F2=2\"
\n" ); document.write( "\"-log%282%2Cx%29%2F2=2-log%282%2Cy%29%2F2\"
\n" ); document.write( "\"log%282%2Cx%29%2F2=log%282%2Cy%29%2F2-2\"
\n" ); document.write( "\"log%282%2Cx%29=log%282%2Cy%29-4\"
\n" ); document.write( "\"log%282%2Cx%29-log%282%2Cy%29=-4\"
\n" ); document.write( "\"log%282%2Cy%29-log%282%2Cx%29=4\", multiplied both sides by negative 1
\n" ); document.write( "\"log%282%2Cy%2Fx%29=4\"
\n" ); document.write( "Put into expon. form.\r
\n" ); document.write( "\n" ); document.write( "\"2%5E4=y%2Fx\"
\n" ); document.write( "\"x%2A2%5E4=y\"
\n" ); document.write( "\"x=y%2F2%5E4\"
\n" ); document.write( "\"highlight%28x=y%2F16%29\"\r
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\n" ); document.write( "\n" ); document.write( "------------not the best form----
\n" ); document.write( "\"x=2%5E%28%28%28log%282%2Cy%29%29-4%29%29\"
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