document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=865774>Question 865774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In how many ways can a committee of six people be chosen from 4 men and 7 women if at least 4 women must be on the committee and Carlo (one of the seven women) must be on the committee </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521873 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since Carlo must be on the committee in reality we have a committee of 5 people with 4 men and six women and at least 3 women must be on it.<BR>\n" );
document.write( "Five women: 6C5 = 6<BR>\n" );
document.write( "4 w + 1 m : 6C4 * 4C1 = 15*4 = 60<BR>\n" );
document.write( "3 w + 2 m : 6C3 * 4C2 = 20*6 = 120<BR>\n" );
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document.write( "6+60+120=186 ways<BR>\n" );
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document.write( "Ed<BR>\n" );
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