document.write( "Question 865801: 6xsq.(2x+3)-5x(2x+3)=4(2x+3) \n" ); document.write( "
Algebra.Com's Answer #521864 by mananth(16946)\"\" \"About 
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6x^2*(2x+3)-5(2x+3)=4(2x+3)\r
\n" ); document.write( "\n" ); document.write( "let 2x+3=a\r
\n" ); document.write( "\n" ); document.write( "6ax^2-5ax=4ax\r
\n" ); document.write( "\n" ); document.write( "6ax^2-5ax-4a=0\r
\n" ); document.write( "\n" ); document.write( "a(6x^2-5x-4)=0\r
\n" ); document.write( "\n" ); document.write( "either a=0
\n" ); document.write( "or (6x^2-5x-4)=0\r
\n" ); document.write( "\n" ); document.write( "If a= 0
\n" ); document.write( "2x+3=0
\n" ); document.write( "x=-3/2
\n" ); document.write( "if 6x^2-5x-4=0
\n" ); document.write( "6x^2-8x+3x-4=0
\n" ); document.write( "2x(3x-4)+1(3x-4)=0
\n" ); document.write( "(3x-4)(2x+1)=0
\n" ); document.write( "3x-4 =0
\n" ); document.write( "Or
\n" ); document.write( "2x+1=0\r
\n" ); document.write( "\n" ); document.write( "x=4/3
\n" ); document.write( "OR
\n" ); document.write( "x=-1/2\r
\n" ); document.write( "\n" ); document.write( "x=-1/2, or -3/2, or 4/3
\n" ); document.write( "
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