document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72957>Question 72957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> m^3+2m^2-3m=0  Solve each equation so Far i have \r<BR>\n" );
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document.write( "M(M^2+2m-3)=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52181 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m^3+2m^2-3m=0  \r<BR>\n" );
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document.write( "M(M^2+2m-3)=0<BR>\n" );
document.write( "Good start, now finish factoring.<BR>\n" );
document.write( "m(m____)(m___)=0  <BR>\n" );
document.write( "fill the blanks with two integers that multiply to give you the last term, -3, but add to give you the middle coefficient, +2.<BR>\n" );
document.write( "3*-1=-3 and 3+(-1)=+2<BR>\n" );
document.write( "m(m+3)(m-1)=0  <BR>\n" );
document.write( "Set each factor equal to 0 and solve:<BR>\n" );
document.write( "m=0 or m+3=0 or m-1=0<BR>\n" );
document.write( "m=0 or m+3-3=0-3 or m-1+1=0+1<BR>\n" );
document.write( "m=0 or m=-3 or m=1<BR>\n" );
document.write( "Happy Calculating!!!!! </SPAN>\n" );
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