document.write( "Question 865482: Divide 20 into two parts such thay three times the square of one part exceeds the other part bye 10 \n" ); document.write( "

Algebra.Com's Answer #521725 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Let x and (20-x) represent the two parts
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document.write( "    3x^2 -10 = (20-x)
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document.write( "    3x^2 + x -30 = 0
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document.write( "    (3x +10)(x-3) = 0,  x =  3      (Tossing out the negative solution for unit measure)
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document.write( "And...Checking
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document.write( "   27 -10 = 20-3 = 17 \n" );
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