document.write( "Question 72944: .018 + 3square root .018(1-.018)/300\r
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document.write( "I tried .018 + 3 sq.root .018(.982)/300
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document.write( ".018 + 3 sq root .017676/300
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document.write( ".018+3 sq root .000058\r
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document.write( "teacher gives answer of .041
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document.write( "how do I get there \n" );
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Algebra.Com's Answer #52170 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! .018 + 3square root .018(1-.018)/300\r \n" ); document.write( "\n" ); document.write( "I tried .018 + 3 sq.root .018(.982)/300 \n" ); document.write( ".018 + 3 sq root .017676/300 \n" ); document.write( ".018+3 sq root .00005892 \n" ); document.write( "You've done fine so far, you'll need a calculator for the square root part unless your supposed to extract the root by hand. \n" ); document.write( ".018+3*.007675936425 \n" ); document.write( ".018+.023027809275 \n" ); document.write( ".041027809275 \n" ); document.write( "Which rounds off to .041 \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |