document.write( "Question 72944: .018 + 3square root .018(1-.018)/300\r
\n" ); document.write( "\n" ); document.write( "I tried .018 + 3 sq.root .018(.982)/300
\n" ); document.write( ".018 + 3 sq root .017676/300
\n" ); document.write( ".018+3 sq root .000058\r
\n" ); document.write( "\n" ); document.write( "teacher gives answer of .041
\n" ); document.write( "how do I get there
\n" ); document.write( "

Algebra.Com's Answer #52170 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
.018 + 3square root .018(1-.018)/300\r
\n" ); document.write( "\n" ); document.write( "I tried .018 + 3 sq.root .018(.982)/300
\n" ); document.write( ".018 + 3 sq root .017676/300
\n" ); document.write( ".018+3 sq root .00005892
\n" ); document.write( "You've done fine so far, you'll need a calculator for the square root part unless your supposed to extract the root by hand.
\n" ); document.write( ".018+3*.007675936425
\n" ); document.write( ".018+.023027809275
\n" ); document.write( ".041027809275
\n" ); document.write( "Which rounds off to .041
\n" ); document.write( "Happy Calculating!!!!
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