Algebra.Com's Answer #5217 by prince_abubu(198)![\"\"](\"/images/stars/stars-09.gif\")  
You can put this solution on YOUR website!
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document.write( "The graph above is for  . One of your vertex lies on the curve. I apologize for the fact that it's quite difficult to draw a triangle that meets what the problem is saying. However, I'll do my best to explain it in words.\r
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document.write( "You know that the base of the triangle will ALWAYS lie in the x-axis. Its length (the base) is ALWAYS the x, since you're measuring from the origin to wherever x is.\r
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document.write( "Now the height of your triangle will depend on where your x is, and what the function will do to it. Actually, the height of your triangle will be the  . Now, hang on because this is where it'll get tricky. After  , will have a negative value. The only thing that happens is that your triangle becomes upside-down, and it'll still have an area. We will force the to be positive by putting it inside absolute value:  . This way, if  , you'll have a positive height for your upside-down triangle.\r
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document.write( "So, the area of the triangle is  . The base B is the x. The height is  . Since the area depends on x and the function , the area of the triange becomes a function of x:\r
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