document.write( "Question 865399: Please help me solve this problem \r
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document.write( "Solve the equation on the interval 0 < x < 2(pi) \r
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document.write( "Sin^2(x) + sin (x) = 0 \n" );
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Algebra.Com's Answer #521677 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! sin^2(x) + sin(x) = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin(x)( sin(x) + 1 ) = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin(x) = 0 or sin(x) + 1 = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin(x) = 0 or sin(x) = -1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = arcsin(0) or x = arcsin(-1)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 0,pi or x = 3pi/2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The three solutions are x = 0, x = pi, x = 3pi/2 \n" ); document.write( " |