document.write( "Question 865399: Please help me solve this problem \r
\n" ); document.write( "\n" ); document.write( "Solve the equation on the interval 0 < x < 2(pi) \r
\n" ); document.write( "\n" ); document.write( "Sin^2(x) + sin (x) = 0
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Algebra.Com's Answer #521677 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
sin^2(x) + sin(x) = 0\r
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\n" ); document.write( "\n" ); document.write( "sin(x)( sin(x) + 1 ) = 0\r
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\n" ); document.write( "\n" ); document.write( "sin(x) = 0 or sin(x) + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "sin(x) = 0 or sin(x) = -1\r
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\n" ); document.write( "\n" ); document.write( "x = arcsin(0) or x = arcsin(-1)\r
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\n" ); document.write( "\n" ); document.write( "x = 0,pi or x = 3pi/2\r
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\n" ); document.write( "\n" ); document.write( "The three solutions are x = 0, x = pi, x = 3pi/2
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