document.write( "Question 865385: The local grocery store sells a gallon of milk for $3.04. If the average price for a gallon of milk is $2.94 with a standard deviation of $0.19, find the z-score for the price of the gallon of milk.\r
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document.write( "How would I find the z score? \n" );
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Algebra.Com's Answer #521667 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! mean: mu = 2.94 (the symbol commonly used is mu = \n" ); document.write( "standard deviation: sigma = 0.19 (the symbol commonly used is sigma = \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Raw Score: x = 3.04\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Z-score\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the z-score is approximately z = 0.52631578947369\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Round that accordingly if you need to (ex: if they want 2 decimal places, then don't forget to round to z = 0.53) \n" ); document.write( " \n" ); document.write( " |