document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=865281>Question 865281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the polar coordinates of the point whose rectangular coordinates are (4sqrt 3, -4)\r<BR>\n" );
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document.write( "Find the rectangular coordinates of the point whose polar coordinates are (-4, &#960;/6).\r<BR>\n" );
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document.write( "Find a rectangular form of the equation r = 5 cos &#952; </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521638 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the polar coordinates of the point whose <BR>\n" );
document.write( "rectangular coordinates are (4sqrt 3, -4)<BR>\n" );
document.write( "Note:: the point is in QIV so the angle is in QIV<BR>\n" );
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document.write( "r = sqrt[(4sqrt(3))^2 + 4^2] = sqrt[64] = 8<BR>\n" );
document.write( "angle = t = arctan(-4/4sqrt(3)) = arctan(-1/sqrt(3)) = (11/6)pi<BR>\n" );
document.write( "Ans: (8,(11/6)pi)<BR>\n" );
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document.write( "Find the rectangular coordinates of the point <BR>\n" );
document.write( "whose polar coordinates are (-4, &#960;/6).<BR>\n" );
document.write( "x = -4(cos(pi/6)) = -4(sqrt(3)/2) = -2sqrt(3)<BR>\n" );
document.write( "y = -4(sin(pi/6)) = -4(1/2) = -2<BR>\n" );
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document.write( "Find a rectangular form of the equation <BR>\n" );
document.write( "r = 5 cos &#952;<BR>\n" );
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document.write( "r = sqrt(x^2+y^2)<BR>\n" );
document.write( "theta = arctan(y/x)<BR>\n" );
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document.write( "Therefore cos(theta) = x/sqrt(x^2+y^2)<BR>\n" );
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document.write( "Substituting you get:<BR>\n" );
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document.write( "sqrt(x^2+y^2) = 5*x/sqrt(x^2+y^2)<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "x^2 + y\"^2 = 5x<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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