document.write( "Question 865184: HELP!!!!
\n" );
document.write( "9a+10b+12c=398
\n" );
document.write( "6a+4b+4c=164
\n" );
document.write( "1a+2b+1c=58
\n" );
document.write( "Solve for a,b,c and show work! \n" );
document.write( "
Algebra.Com's Answer #521626 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 9a + 10b + 12c = 398 \n" ); document.write( "6a + 4b + 4c = 164 \n" ); document.write( "1a + 2b + 1c = 58 \n" ); document.write( "Multiply the 1st equation by-1, the 3rd equations by 3 \n" ); document.write( "-9a - 10b - 12c = -398 \n" ); document.write( " 6a + 4b + 4c = 164 \n" ); document.write( " 3a + 6b + 3c = 174 \n" ); document.write( "---------------------Addition eliminates a & b, find c \n" ); document.write( " 0a + 0b - 5c = -60 \n" ); document.write( "c = -60/-5 \n" ); document.write( "c = +12 \n" ); document.write( ": \n" ); document.write( "using the 2nd and third equations replace c with 12 \n" ); document.write( "6a + 4b + 4(12) = 164 \n" ); document.write( "1a + 2b + 1(12) = 58 \n" ); document.write( ": \n" ); document.write( "6a + 4b = 164 - 48 \n" ); document.write( "1a + 2b = 58 - 12 \n" ); document.write( ": \n" ); document.write( "6a + 4b = 116 \n" ); document.write( "1a + 2b = 46 \n" ); document.write( "multiply the 2nd equation by -2 \n" ); document.write( " 6a + 4b = 116 \n" ); document.write( "-2a - 4b = -92 \n" ); document.write( "-----------------addition eliminates b, find a \n" ); document.write( "4a = 24 \n" ); document.write( "a = 24/4 \n" ); document.write( "a = 6 \n" ); document.write( ": \n" ); document.write( "Use the original 3rd equation to find b \n" ); document.write( "1a + 2b + 1c = 58 \n" ); document.write( "6 + 2b + 12 = 58 \n" ); document.write( "2b = 58 - 18 \n" ); document.write( "2b = 40 \n" ); document.write( "b = 40/2 \n" ); document.write( "b = 20 \n" ); document.write( ": \n" ); document.write( "You can confirm this for yourself in the 1st and 2nd equation \n" ); document.write( " |