document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=865202>Question 865202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sum of the first 10th terms of the geometric sequence -8,-4,-2,... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521623 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r=1/2<BR>\n" );
document.write( "S=t*(1 - r^n)/(1 - r)<BR>\n" );
document.write( "S10=-8*(1 - 1/2^10)/(1 - 1/2)<BR>\n" );
document.write( "S10=-1023/64 \r<BR>\n" );
document.write( "\n" );
document.write( "Tn = t * r^(n - 1)<BR>\n" );
document.write( "T = -8 * 1/2^(9)<BR>\n" );
document.write( "T10=-1/64 </SPAN>\n" );
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