document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=865219>Question 865219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need your help the question is the foundation of a building is in the shape of two adjacent squares. the perimeter of the foundation is 80 m and its area is 325 m^2. find the length of a side of each square. these are the equations i have 4x+ 2y= 80 and x^2 + y^2= 325 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521573 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the foundation of a building is in the shape of two adjacent squares. the perimeter of the foundation is 80 m and its area is 325 m^2. find the length of a side of each square. these are the equations i have 4x+ 2y= 80 and x^2 + y^2= 325<BR>\n" );
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document.write( "4x + 2y = 80 is good for the perimeteter, but<BR>\n" );
document.write( "x^2 + y^2 = 325 is a circle.<BR>\n" );
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document.write( "2xy = 325 is the Area </SPAN>\n" );
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